C++ named requirements: Erasable

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C++ named requirements

Specifies that an object of the type can be destroyed by a given Allocator.


The type T is Erasable from the Container X whose value_type is identical to T if, given

A an allocator type
m an lvalue of type A
p the pointer of type T* prepared by the container

where X::allocator_type is identical to std::allocator_traits<A>::rebind_alloc<T>,

the following expression is well-formed:

std::allocator_traits<A>::destroy(m, p);

If X is not allocator-aware, the term is defined as if A were std::allocator<T>, except that no allocator object needs to be created, and user-defined specializations of std::allocator are not instantiated.


All standard library containers require that their element type satisfies Erasable.

With the default allocator, this requirement is equivalent to the validity of p->~T(), which accepts class types with accessible destructors and all scalar types, but rejects array types, function types, reference types, and void.

See Also