std::optional<T>::operator->, std::optional<T>::operator*

< cpp‎ | utility‎ | optional
constexpr const T* operator->() const;
(1) (since C++17)
constexpr T* operator->();
(1) (since C++17)
constexpr const T& operator*() const&;
(2) (since C++17)
constexpr T& operator*() &;
(2) (since C++17)
constexpr const T&& operator*() const&&;
(2) (since C++17)
constexpr T&& operator*() &&;
(2) (since C++17)

Accesses the contained value.

1) Returns a pointer to the contained value.
2) Returns a reference to the contained value.

The behavior is undefined if *this does not contain a value.



Return value

Pointer or reference to the contained value.




This operator does not check whether the optional contains a value! You can do so manually by using has_value() or simply operator bool(). Alternatively, if checked access is needed, value() or value_or() may be used.


#include <optional>
#include <iostream>
#include <string>
int main()
    using namespace std::string_literals;
    std::optional<int> opt1 = 1;
    std::cout<< "opt1: "  << *opt1 << '\n';
    *opt1 = 2;
    std::cout<< "opt1: "  << *opt1 << '\n';
    std::optional<std::string> opt2 = "abc"s;
    std::cout<< "opt2: " << *opt2 << " size: " << opt2->size() << '\n';
    // You can "take" the contained value by calling operator* on a rvalue to optional
    auto taken = *std::move(opt2);
    std::cout << "taken: " << taken << " opt2: " << *opt2 << "size: " << opt2->size()  << '\n';


opt1: 1
opt1: 2
opt2: abc size: 3
taken: abc opt2: size: 0

See also

returns the contained value
(public member function)
returns the contained value if available, another value otherwise
(public member function)